In the fourth part of Java Puzzlers, we have something related to char type.
You may have guessed it. It will print "b" and the reason for it is that char type is unsigned numeric primitive in the disguise of a character. So if I add one then I'll get the next character in unicode representation.
Then let's take a look at that one
public class Puzzler { public static void main(String[] args){ char myChar = 'a'; myChar++; System.out.println(myChar); } }
You may have guessed it. It will print "b" and the reason for it is that char type is unsigned numeric primitive in the disguise of a character. So if I add one then I'll get the next character in unicode representation.
Then let's take a look at that one
public class Puzzler { public static void main(String[] args){ char myChar = 'a'; System.out.println(myChar + myChar); } }Will this print "aa"? Or  which's 97 + 97 = 194 (where 97 is value of 'a'). I don't know if you guessed it right but the result is neither. It's "194". When Java sees plus it tells "hmm that's an addition not a concat" and adds myChars up and returns the int value for it.
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